Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
In | 882 | 50 | 2 | 25.0000 |
He | 425 | 17 | 1 | 17.0000 |
This | 997 | 48 | 3 | 16.0000 |
As | 257 | 15 | 1 | 15.0000 |
They | 256 | 14 | 1 | 14.0000 |
cent | 279 | 13 | 1 | 13.0000 |
These | 227 | 11 | 1 | 11.0000 |
am | 139 | 11 | 1 | 11.0000 |
It | 781 | 28 | 3 | 9.3333 |
We | 560 | 28 | 3 | 9.3333 |
The | 4655 | 277 | 30 | 9.2333 |
And | 127 | 9 | 1 | 9.0000 |
1916 | 75 | 9 | 1 | 9.0000 |
past | 111 | 9 | 1 | 9.0000 |
But | 155 | 9 | 1 | 9.0000 |
be | 3228 | 225 | 27 | 8.3333 |
1956 | 85 | 8 | 1 | 8.0000 |
Students | 93 | 8 | 1 | 8.0000 |
She | 134 | 8 | 1 | 8.0000 |
1938 | 69 | 8 | 1 | 8.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Report | 1906 | 4 | 120 | 0.0333 |
Bulletin | 207 | 1 | 27 | 0.0370 |
Biennial | 216 | 2 | 37 | 0.0541 |
Journal | 314 | 2 | 37 | 0.0541 |
Dept | 194 | 1 | 14 | 0.0714 |
Yearbook | 57 | 1 | 10 | 0.1000 |
able | 187 | 1 | 10 | 0.1000 |
Vision | 243 | 1 | 10 | 0.1000 |
part | 323 | 2 | 20 | 0.1000 |
M. | 113 | 1 | 9 | 0.1111 |
Reports | 304 | 5 | 37 | 0.1351 |
range | 129 | 1 | 7 | 0.1429 |
Experiment | 89 | 1 | 7 | 0.1429 |
Papua | 100 | 1 | 7 | 0.1429 |
carried | 56 | 1 | 7 | 0.1429 |
Committee | 1202 | 5 | 34 | 0.1471 |
Board | 482 | 3 | 19 | 0.1579 |
Division | 393 | 3 | 18 | 0.1667 |
W. | 75 | 1 | 6 | 0.1667 |
Office | 772 | 6 | 34 | 0.1765 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II